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Home/ Questions/Q 4594922
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Editorial Team
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Editorial Team
Asked: May 21, 20262026-05-21T22:53:47+00:00 2026-05-21T22:53:47+00:00

when I am executing this on the command line: awk ‘BEGIN{OFS=FS=,}$3~/^353/{print}’ axeM10_20110510100219_59.DAT_353 >log it

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when I am executing this on the command line:

awk 'BEGIN{OFS=FS=","}$3~/^353/{print}' axeM10_20110510100219_59.DAT_353 >log

it executes vey nicely without taking much time and instantly gives me the output file.

but when I am including this in a shell script :

#!/usr/bin/ksh

for i in *.DAT_353
do
awk 'BEGIN{OFS=FS=","}$3~/^353/{print}'  ${i} > ${i}_changed >/dev/null
done

exit

the script is generating a 0 byte files.
may I know what is the problem here?

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  1. Editorial Team
    Editorial Team
    2026-05-21T22:53:48+00:00Added an answer on May 21, 2026 at 10:53 pm

    Remove >/dev/null because that is where your stdout is being redirected to.

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