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Home/ Questions/Q 7457991
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Editorial Team
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Editorial Team
Asked: May 29, 20262026-05-29T13:23:32+00:00 2026-05-29T13:23:32+00:00

When I am running this function the value is showing up as 26. I

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When I am running this function the value is showing up as 26. I want to know what calculation the system uses and why it is evaluating to 26.

<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<meta http-equiv="Content-Type" content="text/html; charset=utf-8" />
<title>parseint</title>

<script type="text/javascript">

var par= "1a";

alert (parseInt(par,16))

</script>

</head>

<body>


</body>
</html>
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  1. Editorial Team
    Editorial Team
    2026-05-29T13:23:33+00:00Added an answer on May 29, 2026 at 1:23 pm

    The second argument of parseInt is the radix. It shows what base to use. Base 16 is hexadecimal, and 1a in base 16 is 26 in base 10 (decimal).

    This is why it’s important to always specify the radix when using parseInt. In this case, not supplying the radix will result in the value 1, because it attempts to parse the number in base 10, gets to the character a, gives up and returns what it has found so far:

    parseInt("1a"); //1
    parseInt("1a", 10); //1 (same as above)
    parseInt("1a", 16); //26
    

    However, if the number begins with the characters 0x or 0X, it is assumed to be a hexadecimal number, and you can omit the radix (although it’s recommended to always pass the radix to avoid unwanted side effects):

    parseInt("0x1a"); //26
    
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