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Home/ Questions/Q 8948545
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Editorial Team
  • 0
Editorial Team
Asked: June 15, 20262026-06-15T13:01:11+00:00 2026-06-15T13:01:11+00:00

When I am trying to open the screen I got the following exception: Unable

  • 0

When I am trying to open the screen I got the following exception:

Unable to cast object of type ‘System.Windows.Controls.Grid’ to type ‘System.Windows.Controls.TabItem’

Any help will be appreciated.

partial void VouchersDetail_Created()
    {
        this.FindControl("JournalVoucher").ControlAvailable += JournalVoucher_ControlAvailable;
    }

    void JournalVoucher_ControlAvailable(object sender, ControlAvailableEventArgs e)
    {
        ((System.Windows.Controls.TabItem)e.Control).KeyUp += JournalVoucher_KeyUp;
    }

    void JournalVoucher_KeyUp(object sender, KeyEventArgs e)
    {
        if (e.Key == Key.V)
        {
            if ((Keyboard.Modifiers & ModifierKeys.Control) == ModifierKeys.Control)
            {
                var tabitem = (System.Windows.Controls.TabItem)sender;
                tabitem.IsEnabled = true;
            }
        }
    }

Thanks

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  1. Editorial Team
    Editorial Team
    2026-06-15T13:01:12+00:00Added an answer on June 15, 2026 at 1:01 pm

    My guess is that JournalVoucher is of type Grid. And you are trying to cast that to the type TabItem.

    Put a breakpoint on the line and check if the event gets called more than once.

    If it only gets called once than it may be enough to change the line

    ((System.Windows.Controls.TabItem)e.Control).KeyUp += JournalVoucher_KeyUp;
    

    to:

    ((System.Windows.Controls.Grid)e.Control).KeyUp += JournalVoucher_KeyUp;
    

    Most likely the Sender in JournalVoucher_KeyUp is also of type Grid

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