Question

When I call next() I have an extraneous [] in @current. How can I fix this?

class Result    
  attr_accessor :current

  def initialize(*previous)
    @current = previous
    p @current
  end

  def next()
    res = Result.new(@current)
  end
end

res = Result.new([2,2], [3,3], [4,4])
nextArray = res.next

Answer 1

Your first call has 3 parameters, whereas the call in next() has only one.

try:

def next()
  res = Result.new(*@current)
end