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Home/ Questions/Q 7961949
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Editorial Team
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Editorial Team
Asked: June 4, 20262026-06-04T05:11:44+00:00 2026-06-04T05:11:44+00:00

when i call this function I am not getting a return value to use

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when i call this function I am not getting a return value to use in my other function that called it. I know this request works as I can use alert() and see the value is there. Any ideas would be greatly appreciated.

function GetRepName(InputStr1){
  var name = '';
  $.post("getrepname.php", {queryString: ""+InputStr1+""}, function(data){
    if(data.length >0) {
      $('#Results'+InputStr1).html(data);
      name = data;
    }
  });
  return name;
}

The posts I have read so far suggest having the variable defined in the outer function and then returned but this doesn’t seem to be working. do I need to add some code that will wait for the value to be returned before issuing the return statement?

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  1. Editorial Team
    Editorial Team
    2026-06-04T05:11:45+00:00Added an answer on June 4, 2026 at 5:11 am

    The thing is that the $.post callback is called asynchronously, i.e. after the function has returned. You could make the AJAX call synchronously, but this isn’t recommended. You are better off re-designing your code taking into account the asynchronous nature of requests.

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