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Home/ Questions/Q 7950837
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Editorial Team
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Editorial Team
Asked: June 4, 20262026-06-04T02:23:16+00:00 2026-06-04T02:23:16+00:00

When I constrain T with : Object like this: public interface IDoWork<T> where T

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When I constrain T with : Object like this:

public interface IDoWork<T> where T : Object
{
    T DoWork();
}

I get the error:

Constraint cannot be special class ‘object’

Does that mean there is an implied difference with the following that does compile?

public interface IDoWork<T> // where T : Object
{
    T DoWork();
}
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  1. Editorial Team
    Editorial Team
    2026-06-04T02:23:18+00:00Added an answer on June 4, 2026 at 2:23 am

    There is no difference between the two constraints, except for that one is disallowed for being useless to explicitly state.

    The C# 4.0 language specification (10.1.5 Type parameter constraints) says two things about this:

    The type must not be object. Because all types derive from object,
    such a constraint would have no effect if it were permitted.

    …

    If T has no primary constraints or type parameter constraints, its
    effective base class is object.

    In your comment, you said that you were trying to make T be of type Void. Void is a special type that indicates that there is no return type and cannot be used in place of T, which requires an appropriate concrete type. You will have to create a void version of your method and a T version if you want both.

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