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Home/ Questions/Q 8837351
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Editorial Team
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Editorial Team
Asked: June 14, 20262026-06-14T09:42:06+00:00 2026-06-14T09:42:06+00:00

When I create a new F# Application under Visual Studio 2012 and build it,

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When I create a new F# Application under Visual Studio 2012 and build it, the same error occur:

Error 1 The OutputPath property is not set for project ‘TestingF.fsproj’. Pleasecheck to make sure that you have specified a valid combination of Configuration and Platform for this project. Configuration=’Debug’ Platform=”. This error may also appear if some other project is trying to follow a project-to-project reference to this project, this project has been unloaded or is not included in the solution, and the referencing project does not build using the same or an equivalent Configuration or Platform. C:\Windows\Microsoft.NET\Framework\v4.0.30319\Microsoft.Common.targets 592 5 TestingF

Tried to modify the Configuration|Platform using Configuration Manager and also unload the project and edit the .fsproj file.

<PropertyGroup Condition=" '$(Configuration)|$(Platform)' == 'Debug|AnyCPU' ">
<DebugSymbols>true</DebugSymbols>
<DebugType>full</DebugType>
<Optimize>false</Optimize>
<Tailcalls>false</Tailcalls>
<OutputPath>bin\Debug\</OutputPath>
<DefineConstants>DEBUG;TRACE</DefineConstants>
<WarningLevel>3</WarningLevel>
<PlatformTarget>AnyCPU</PlatformTarget>
<DocumentationFile>bin\Debug\TestingF.XML</DocumentationFile>
<Prefer32Bit>true</Prefer32Bit>
</PropertyGroup>

The same error never occurred using any other .Net Language.

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-14T09:42:07+00:00Added an answer on June 14, 2026 at 9:42 am

    Take a look at the error:

    […] make sure that you have specified a valid combination of Configuration and Platform for this project. Configuration=’Debug’ Platform=”. This error may also appear […]

    Visual Studio is trying to build Platform=”, Configuration=’Debug’. The project file you posted, however, specifies the following configuration:

    <PropertyGroup Condition=" '$(Configuration)|$(Platform)' == 'Debug|AnyCPU' ">
        . . .
    </PropertyGroup>
    

    That is, it tells Visual Studio how to build ‘Debug’/’AnyCPU’, but not ‘Debug’/’ ‘.

    If you insert ‘AnyCPU’ in there, it should give you the results you’re looking for.

    A more elaborate answer can be found here: https://stackoverflow.com/a/13372073/556595

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