Question

When I create Java Class in Eclipse which implements Serializable interface, I get a warning

The serializable class ABCD does not declare a static final
serialVersionUID field of type long

So when I click on warning, I get a option in Eclipse to

Add generated Serial Version ID

Once I choose that option, Eclipse automatically creates a serialVersionUID variable for me.

Now I wanted to know that on what basis that number is generated. It is a just any random number ? Can I provide any random number of my own ?

Answer 1

It is calculated based on the structure of your class – fields, methods, etc. It is specified in the Object Serialization Specification – see this section for the exact format.

The spec describes what happens in no value is provided, but the autogeneration uses the same algorithm.

The sequence of items in the stream is as follows:

• The class name.
• The class modifiers written as a 32-bit integer.
• The name of each interface sorted by name.
• For each field of the class sorted by field name (except private static and private transient fields:
  • The name of the field.
  • The modifiers of the field written as a 32-bit integer.
  • The descriptor
    of the field.
• If a class initializer exists, write out the following:
  • The name of the method, .
  • The modifier of the method, java.lang.reflect.Modifier.STATIC, written as a 32-bit integer.
  • The descriptor of the method, ()V.
• For each non-private constructor sorted by method name and signature:
  • The name of the method, .
  • The modifiers of the method written as a 32-bit integer.
  • The descriptor of the method.
• For each non-private method sorted by method name and signature:
  • The name of the method.
  • The modifiers of the method written as a 32-bit integer.
  • The descriptor of the method.