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Home/ Questions/Q 8433245
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Editorial Team
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Editorial Team
Asked: June 10, 20262026-06-10T06:20:05+00:00 2026-06-10T06:20:05+00:00

When I do something like this int test = 5 + 3 * (4

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When I do something like this

int test = 5 + 3 * (4 - 1) / 2;

I get 9. I suspected this was because int rounds down. However, when I do this

float test = 5 + 3 * (4 - 1) / 2;

I also get 9. However, when I do this

float test1 = 5;
float test2 = 4.5;
float test = test1 + test2;

Test finally outputs 9.5. Could someone explain the logic behind this? Why don’t I get 9.5 in the second example? Thanks.

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  1. Editorial Team
    Editorial Team
    2026-06-10T06:20:07+00:00Added an answer on June 10, 2026 at 6:20 am

    In your second example, although you are assigning the result to a variable of type float, the calculation itself is still performed exactly the same way as the first example. Java does not look at the destination variable type to determine how to calculate the right hand side. In particular, the subexpression 3 * (4 - 1) / 2 results in 4.

    To fix this, you can use floating point literals instead of all integers:

    float test = 5 + 3 * (4 - 1) / 2.0f;
    

    Using 2.0f triggers floating point calculations for the arithmetic expression.

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