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Home/ Questions/Q 5983979
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Editorial Team
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Editorial Team
Asked: May 22, 20262026-05-22T22:18:30+00:00 2026-05-22T22:18:30+00:00

When I do: std::string name = targetBone->getName(); if(name == Pelvis) { return; } I

  • 0

When I do:

std::string name = targetBone->getName();
    if(name == "Pelvis")
    {
        return;
    }

I get:

Error 1 error C2678: binary '==' : no operator found which takes a left-hand operand of type 'std::string' (or there is no acceptable conversion)

How do I resolve this error ?

Thanks

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  1. Editorial Team
    Editorial Team
    2026-05-22T22:18:31+00:00Added an answer on May 22, 2026 at 10:18 pm

    Have you included string in your cpp file

    #include <string>
    

    This usually happens because the compiler need to see the definition of string class that resides in that included file to verify that it indeed declares an operator that takes a char*

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