When I do this:
main(){
char* output[255];
output[0] = '\0';
}
I get a segfault at output[0] = '\0'.
What am I doing wrong?
When I do this: main(){ char* output[255]; output[0] = ‘\0’; } I get a
Share
Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.
Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.
Lost your password? Please enter your email address. You will receive a link and will create a new password via email.
Please briefly explain why you feel this question should be reported.
Please briefly explain why you feel this answer should be reported.
Please briefly explain why you feel this user should be reported.
When I do this:
main(){
char* output[255];
output[0] = '\0';
}
I get a segfault at output[0] = '\0'.
What am I doing wrong?
The problem is probably somewhere else, this part of code shouldn’t segfault. Maybe you try to print it somewhere?
However I’m not sure whether it does what you want. You declared array of char pointers:
And write char there:
You probably wanted to declare array of chars: