Question

When I execute the following svn command, I get the below output.

$ svn log -r 1:HEAD --limit 1 http://plugins.svn.wordpress.org/bulk-delete
------------------------------------------------------------------------
r91525 | plugin-master | 2009-02-03 10:39:23 +0530 (Tue, 03 Feb 2009) | 1 line

adding bulk-delete by sudar
------------------------------------------------------------------------

I am writing a shell script and I want to parse the output of the above command and get the revision number (r91525 in this case) and store it in a shell variable, so that I can use it in the subsequent commands.

I tried the cut command and was able to get the revision number in the second line, but the other lines were still appearing.

$ svn log -r 1:HEAD --limit 1 http://plugins.svn.wordpress.org/bulk-delete | cut -f1 -d'|'
------------------------------------------------------------------------
r91525 

adding bulk-delete by sudar
------------------------------------------------------------------------

Question: How to retrieve the revision number and store in a shell variable, so that I can use it in the subsequent commands?

Answer 1

You can use sed for this.

  svn log --limit 1 | sed -n -e 's/^\(r[0-9]\+\).*/\1/p'

this will print out only the revision e.g. r1234

If you need only the number of the revision use

  svn log --limit 1 | sed -n -e 's/^r\([0-9]\+\).*/\1/p'

UPDATE: to store it in a variable use

bash:

REVISION=$(svn log --limit 1 | sed -n -e 's/^r\([0-9]\+\).*/\1/p')

tcsh

  set revision = `svn log --limit 1 | sed -n -e 's/^r\([0-9]\+\).*/\1/p'`