Question

When i give wrong number of parameters in a function , i get errors. How do I handle it?

I gave

def fun_name(...):     try:         ...      except TypeError:         print 'Wrong no of arg' 

It is not working.

Help please.

Answer 1

The caller triggers this exception, not the receiver.

If you want the receiving function to explicitly check argument count you’ll need to use varargs:

def fun_name(*args):   if len(args) != 2:     raise TypeError('Two arguments required')