Sign Up

Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.

Have an account? Sign In

Have an account? Sign In Now

Sign In

Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.

Sign Up Here

Forgot Password?

Don't have account, Sign Up Here

Forgot Password

Lost your password? Please enter your email address. You will receive a link and will create a new password via email.

Have an account? Sign In Now

You must login to ask a question.

Forgot Password?

Need An Account, Sign Up Here

Please briefly explain why you feel this question should be reported.

Please briefly explain why you feel this answer should be reported.

Please briefly explain why you feel this user should be reported.

Sign InSign Up

The Archive Base

The Archive Base Logo The Archive Base Logo

The Archive Base Navigation

  • SEARCH
  • Home
  • About Us
  • Blog
  • Contact Us
Search
Ask A Question

Mobile menu

Close
Ask a Question
  • Home
  • Add group
  • Groups page
  • Feed
  • User Profile
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Buy Points
  • Users
  • Help
  • Buy Theme
  • SEARCH
Home/ Questions/Q 6088059
In Process

The Archive Base Latest Questions

Editorial Team
  • 0
Editorial Team
Asked: May 23, 20262026-05-23T11:56:30+00:00 2026-05-23T11:56:30+00:00

When I look up an xpath with b.xpath(td[@class=’team’]/img).each do |d| puts d[‘id’] end The

  • 0

When I look up an xpath with

b.xpath("td[@class='team']/img").each do |d|
  puts d['id']
end

The element “d” is a html node. I can reference attributes in it.

But when I attempt to look up the same element in one line, it gets returned as a string.

c = b.xpath("td[@class='team']/img")[0]

There is only one element I in the array, I don’t need to loop through anything .each. Is there a way to make this one line?

  • 1 1 Answer
  • 0 Views
  • 0 Followers
  • 0
Share
  • Facebook
  • Report

Leave an answer
Cancel reply

You must login to add an answer.

Forgot Password?

Need An Account, Sign Up Here

1 Answer

  • Voted
  • Oldest
  • Recent
  • Random
  1. Editorial Team
    Editorial Team
    2026-05-23T11:56:30+00:00Added an answer on May 23, 2026 at 11:56 am

    I ended up doing something like this:

    t = a.xpath("tr/td[@class='team']/img")
    away = t[0]['id']
    home = t[1]['id']
    
    • 0
    • Reply
    • Share
      Share
      • Share on Facebook
      • Share on Twitter
      • Share on LinkedIn
      • Share on WhatsApp
      • Report

Sidebar

Related Questions

I wrote a Xpath query to look for an element with a nodeValue that
I am trying to find an element located at xpath = //html[1]/body[1]/div[1]/div[2]/div[1]/div[2]/p[1] In Firefox
Look at this situation: www.websitea.com displays an img tag with a src attribute of
look at this code, <head> <meta http-equiv=Content-Type content=text/html; charset=utf-8 /> <script> function change() {
Look at the following two ways to create a new object of class Y:
Look at this code: class MyClass(): # Why does this give me NameError: name
look the UML image. I've got a generic class called BinaryProblem, this one receives
You can look at the code in question at: https://test.fuzebox.com Greetings! I ran across
Using lxml in python I created this xpath syntax htmlPage.xpath(/html/body//a/text()) It gets me all
I'm a little new to xpath and I was wondering if you anyone can

Explore

  • Home
  • Add group
  • Groups page
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Users
  • Help
  • SEARCH

Footer

© 2021 The Archive Base. All Rights Reserved
With Love by The Archive Base

Insert/edit link

Enter the destination URL

Or link to existing content

    No search term specified. Showing recent items. Search or use up and down arrow keys to select an item.