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Home/ Questions/Q 6981533
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Editorial Team
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Editorial Team
Asked: May 27, 20262026-05-27T18:10:10+00:00 2026-05-27T18:10:10+00:00

When I override the clone() method of a Backbone.Model , is there a way

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When I override the clone() method of a Backbone.Model, is there a way to call this overriden method from my implantation? Something like this:

var MyModel = Backbone.Model.extend({
    clone: function(){
        super.clone();//calling the original clone method
    }
})
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  1. Editorial Team
    Editorial Team
    2026-05-27T18:10:10+00:00Added an answer on May 27, 2026 at 6:10 pm

    You’ll want to use:

    Backbone.Model.prototype.clone.call(this);
    

    This will call the original clone() method from Backbone.Model with the context of this(The current model).

    From Backbone docs:

    Brief aside on super: JavaScript does not provide a simple way to call
    super — the function of the same name defined higher on the prototype
    chain. If you override a core function like set, or save, and you want
    to invoke the parent object’s implementation, you’ll have to
    explicitly call it.

    var Note = Backbone.Model.extend({
     set: function(attributes, options) {
     Backbone.Model.prototype.set.apply(this, arguments);
     ...
     }    
    });
    
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