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Asked: May 10, 20262026-05-10T22:59:35+00:00 2026-05-10T22:59:35+00:00

When I pass an immutable type object(String, Integer,.. ) as final to a method

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When I pass an immutable type object(String, Integer,.. ) as final to a method I can achieve the characters of a C++ constant pointer. But how can I enforce such behavior in objects which are mutable?

public void someMethod(someType someObject){  /*   * code that modifies the someObject's state   *    */ } 

All I want is to prevent someMethod from modifying the state of someObject without making any change in someType. Is this possible?

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  1. 2026-05-10T22:59:36+00:00Added an answer on May 10, 2026 at 10:59 pm

    No, I don’t think this is possible. The normal approach is to create an adapter for SomeType where all the methods changing state throws UnsupportedOperationException. This is used by for instance java.util.Collections.unmodifiable*-functions.

    There are several approaches to this:

    • you can let SomeType be an interface, and when you need it to be read only, just create a wrapper delegating all the read-methods to the original object and implementing all the write-methods to throw an exception.
    • or you can create a subclass of SomeType overriding all the write methods

    This will of course only give you run-time checking, not compiletime. If you want compile-time, you can let SomeType be an interface (or a superclass) with no write-methods, only read.

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