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Home/ Questions/Q 3670804
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Editorial Team
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Editorial Team
Asked: May 19, 20262026-05-19T02:24:35+00:00 2026-05-19T02:24:35+00:00

When I put forexample this in my xslt-stylesheet: <link><xsl:text>test</xsl:text></link> Or this: <link>test</link> I get

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When I put forexample this in my xslt-stylesheet:

<link><xsl:text>test</xsl:text></link>

Or this:

<link>test</link>

I get the following result:

<link xmlns=""></link>

This however:

<linkb>test</linkb>

Render the following result:

<linkb xmlns="">test</linkb>

The rest of the xslt does not seem to make any difference, i’ve tried it in several different and empty xslt-stylesheets

This problem appears in backend conversion (php) aswell as frontend-konversion in chrome browser (but not in Firefox)

Example of error:
dev.resihop.nu
(right above the footer)

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-19T02:24:36+00:00Added an answer on May 19, 2026 at 2:24 am

    It’s not really an XSLT issue.

    <link xmlns="">
    

    Is rendered by Chrome, problem is with built-in browser CSS:

    link {
        display: none;
        }
    

    You can see this with Chrome developer toolbar (just press Ctrl-Shift-I). I think it’s also a reason of no rendering of tag’s content. I guess Chrome just don’t like elements with such names and treats them specifically.

    Edit. And actually I do understand, why. Because of the link tag, which we all use in head section.

    In fact the simpliest way to avoid issues like yours — is to pick any suitable (X)HTML doctype and make your code valid, according to that doctype.

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