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Home/ Questions/Q 598133
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Editorial Team
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Editorial Team
Asked: May 13, 20262026-05-13T16:21:21+00:00 2026-05-13T16:21:21+00:00

when I run it in the terminal (bash) echo -e .\c prints out .

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when I run it in the terminal (bash)

echo -e ."\c"

prints out . and suppresses the newline.

When I run the following script (all the code)

echo -e ."\c"
echo -e ."\c"

it prints out .. and suppresses the newlines.

when I run it inside a script with the shebang (!#/bin/sh), it prints out -e . -e . and suppresses the newline.

Why? and how can I prevent this?

EDIT:
I want to prevent the -e‘s from printing out, so my output should be . .

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  1. Editorial Team
    Editorial Team
    2026-05-13T16:21:21+00:00Added an answer on May 13, 2026 at 4:21 pm

    change your script shebang to #!/bin/bash instead of #!/bin/sh and see if it works

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