Question

When I run my code and use the files that are in the resource folder of my project itself, I face no problems. It zips the file successfully and I can extract it using WINZIP. The problem comes when I try to zip a file that is not in the project folder.

When I do the same, I am passing the Absolute Path of both the src and the dest files. My program doesn’t give any exceptions, but when I try to open that zip file, I get an error saying, File is Invalid.

Can anyone tell me why this may be happening.

public static void compress(String srcPath, String destPath) {

    srcFile = new File(srcPath);
    destFile = new File(destPath);
    try {
        fileInputStream = new FileInputStream(srcFile);
        fileOutputStream = new FileOutputStream(destFile);
        zipEntry = new ZipEntry(srcPath);
        zipOutputStream = new ZipOutputStream(fileOutputStream);
        zipOutputStream.putNextEntry(zipEntry);
        byte[] data = new byte[12];
        while ((fileInputStream.read(data)) != -1) {
            zipOutputStream.write(data);
        }
    } catch (Exception e) {
        e.printStackTrace();
    } finally {
        try{
            fileInputStream.close();
        zipOutputStream.close();}catch (Exception e) {
            e.printStackTrace();
        }
    }

}

Answer 1

You should not store paths with drive letters in your zip file because when you try to extract your zip, it will try to create a directory with the name of the drive and fail.

You will need to change your code so that it removes the drive letter from the path before creating the ZipEntry.