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Home/ Questions/Q 8746265
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Editorial Team
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Editorial Team
Asked: June 13, 20262026-06-13T12:10:04+00:00 2026-06-13T12:10:04+00:00

When I run my program I get the following exception: Exception in thread main

  • 0

When I run my program I get the following exception:

Exception in thread "main" java.lang.ArrayIndexOutOfBoundsException: 1
        at eraKevgiri.main(eraKevgiri.java:29)

What is the problem with this code?

public static void main(String[] args) {
    int gSayi = 0;
    int kKok = (int) Math.sqrt(gSayi);
    boolean[] liste = new boolean[gSayi + 1];

    Scanner klavye = new Scanner(System.in);
    System.out.println("Sayı Girin:");
    gSayi = klavye.nextInt();

    for(int i=2; i<=kKok; i++){
        System.out.println("" +i);
        for(int j=i*i; j<=gSayi; j+=i){
            liste[j] = true;
        }
    }

    for(int k=kKok; k<=gSayi; k++){ 
        if(!liste[k]){ //-------> problem in here
            System.out.println("" + k);
        }
    }
    klavye.close();
}
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  1. Editorial Team
    Editorial Team
    2026-06-13T12:10:05+00:00Added an answer on June 13, 2026 at 12:10 pm

    You should move

    Scanner klavye = new Scanner(System.in);
    System.out.println("Sayı Girin:");
    gSayi = klavye.nextInt();
    

    to the beginning of the method, otherwise the array will always have only one element and then of course there is no element with index 1.

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