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Home/ Questions/Q 9171707
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Editorial Team
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Editorial Team
Asked: June 17, 20262026-06-17T16:12:00+00:00 2026-06-17T16:12:00+00:00

When I run the /bin/bash process with 2 parameters -c and SomeUserInput , where

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When I run the /bin/bash process with 2 parameters -c and SomeUserInput,

where SomeUserInput is echo $TERM

The output is

xterm-256color

Is there a way I can set the value of $TERM via a command line parameter to /bin/bash so the above invokation of echo $TERM would print something else that I specify?

(Yes, I’ve done a lot of digging in man bash and searching elsewhere, but couldn’t find the answer; although I think it’s likely there.)

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  1. Editorial Team
    Editorial Team
    2026-06-17T16:12:00+00:00Added an answer on June 17, 2026 at 4:12 pm

    First of all, since you used double quotes, that prints the value of TERM in your current shell, not the bash you invoke. To do that, use /bin/bash -c 'echo $TERM'.

    To set the value of TERM, you can export TERM=linux before running that command, set it only for that shell with either TERM=linux /bin/bash -c 'echo $TERM' (shell expression), or /usr/bin/env TERM=linux /bin/bash -c 'echo $TERM' (execve compatible (as for find -exec)).

    Update:
    As for your edit of only using command line parameters to /bin/bash, you can do that without modifying your input like this:

    /bin/bash -c 'TERM=something; eval "$1"' -- 'SomeUserInput'
    
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