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Home/ Questions/Q 504083
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Editorial Team
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Editorial Team
Asked: May 13, 20262026-05-13T06:27:36+00:00 2026-05-13T06:27:36+00:00

When I run the code below it removes deleted_partner from B . But as

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When I run the code below it removes deleted_partner from B. But as it removes it from B it also removes it from A. So that when I try to remove it from A the program crashes. What is the problem?

for deleted_partner in self.list_of_trading_partners: 
    B = A[:]
    print("t", deleted_partner)
    print(B[self.ID].list_of_trading_partners)
    B[self.ID].list_of_trading_partners.remove(deleted_partner)
    Round_neo_classic(B)
    Round_costs(B)
    if B[self.ID].final_good > reference_value:
        print("d", deleted_partner)
        print(A[self.ID].list_of_trading_partners)
        A[self.ID].list_of_trading_partners.remove(deleted_partner)

Output:

('t', 1)
[1, 2, 3, 4]
('d', 1)
[2, 3, 4]
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  1. Editorial Team
    Editorial Team
    2026-05-13T06:27:36+00:00Added an answer on May 13, 2026 at 6:27 am

    B=A[:] does copy only the list, but not it’s contents. B[self.ID] and A[self.ID] still reference the same object, only A and B are different.

    You might way to explicitly copy all the elements of the list too – copy.deepcopy can do this. But beware: deepcopy copies everything – it looks like you only want to copy the list_of_trading_partners, so you should probably write a __deepcopy__ method on whatever class A[self.ID] is that does just that.

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