Question

When I run the code below when $entry = miami.com, I get the following error message:

SELECT COUNT(*) FROM #&*+ WHERE `site`
LIKE 'miami.com':You have an error in
your SQL syntax; check the manual that
corresponds to your MySQL server
version for the right syntax to use
near '' at line 1

It looks like I’m not correctly defining $table. Any ideas how I could do that?

Thanks in advance,

John

    $result = mysql_query("SHOW TABLES FROM feather") 
or die(mysql_error()); 


while(list($table)= mysql_fetch_row($result))
{
  $sqlA = "SELECT COUNT(*) FROM $table WHERE `site` LIKE '$entry'";
  $resA = mysql_query($sqlA) or die("$sqlA:".mysql_error());
  list($isThere) = mysql_fetch_row($resA);
  if ($isThere)
  {
     $table_list[] = $table;
  }
}

Answer 1

if it were me debugging that i would see what

print_r(mysql_fetch_row($result));

outputs