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Home/ Questions/Q 848331
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Editorial Team
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Editorial Team
Asked: May 15, 20262026-05-15T06:55:38+00:00 2026-05-15T06:55:38+00:00

When i run this code alert 2 shows 6 different href links. alert 3

  • 0

When i run this code alert 2 shows 6 different href links. alert 3 shows the last href 6 times. How do i make it use the same object (linkdom aka thelink) as alert 2.

NOTE: This is in a greasemonkey script

    {
        var linkdom = thelink;
        alert('2' + linkdom.getAttribute("href"));
        GM_xmlhttpRequest({
            method: 'GET',
            url: href,
            onload: function(resp){
                //...
                alert('3' + linkdom.getAttribute("href"));
            }
        });
    //...
    }
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-15T06:55:38+00:00Added an answer on May 15, 2026 at 6:55 am

    If this were your own function, I’d say to pass it in as a parameter. Or if JavaScript had default parameters, I’d say pass it in as a default parameter. The way it is now, though… try this.

    {
        var linkdom = thelink;
        alert('2' + linkdom.getAttribute("href"));        
        GM_xmlhttpRequest({
            method: 'GET',
            url: href,
            onload: (function() { 
                  var localvar = linkdom; 
                  return function(resp){
                    //...
                    alert('3' + localvar.getAttribute("href"));
                  }})()
        });
    //...
    }
    

    This creates an outer function and sets a local variable to the current value of linkdom. It then creates your function and returns it. I then immediately apply the outer function to get your function back. The outer functions won’t share the same local variable, so the code should work.

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