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Home/ Questions/Q 6714591
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Editorial Team
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Editorial Team
Asked: May 26, 20262026-05-26T08:30:49+00:00 2026-05-26T08:30:49+00:00

When I run this code the program freezes,why? main() { int co; co=0; while

  • 0

When I run this code the program freezes,why?

main()
{
int co;
    co=0;
    while (co<10) {

        co=co+1;

        if (co==3)
            printf("The number is now three.");
        if (co==7)
            printf("The number is now seven.");
        else
            printf(co);

}
}

I’m compiling it with mingw GCC.

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  1. Editorial Team
    Editorial Team
    2026-05-26T08:30:49+00:00Added an answer on May 26, 2026 at 8:30 am

    You can’t print co like that:

    You need to do it like this:

    printf("%d",co);
    

    printf takes as a first parameter, a string with format specifiers. The latter (optional) parameters are the arguments themselves.

    http://www.cplusplus.com/reference/clibrary/cstdio/printf/

    Here’s a more cleaned version of your code:

    int main(){
    
        int co = 0;
        while (co < 10) {
    
            co = co + 1;
    
            if (co == 3)
                printf("The number is now three.");
            if (co == 7)
                printf("The number is now seven.");
            else
                printf("%d\n",co);
        }
    
        return 0;
    }
    
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