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Home/ Questions/Q 6149749
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Editorial Team
  • 0
Editorial Team
Asked: May 23, 20262026-05-23T19:30:21+00:00 2026-05-23T19:30:21+00:00

When i run this program, it appears that sometimes 55 will be printed out,

  • 0

When i run this program, it appears that sometimes 55 will be printed out, although i am certain that 6 is the correct behavior.

Or could it be that i was seeing wrong?

public class Test {
    static int a = 55;

    static {
        a = 6;
    }

    public static void main(String abc[]){
        // a is 6
        System.out.println(a);
    }
}

Edit

I think Cularis got it right, when i shifted the order of the static block and the instantiation and initialization, 55 is printed. It is indeed in texture order.

public class Test {
    static {
        a = 6;
    }

    static int a = 55;

    public static void main(String abc[]) {
        // a is 55
        System.out.println(a);
    }
}
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-23T19:30:22+00:00Added an answer on May 23, 2026 at 7:30 pm

    Have a look at the Java Language Specification, especially

    12.4.2 Detailed Initialization Procedure

    … Next, execute either the class variable initializers and static
    initializers of the class, or the field initializers of the interface,
    in textual order, as though they were a single block, except that
    final class variables and fields of interfaces whose values are
    compile-time constants are initialized first (§8.3.2.1, §9.3.1,
    §13.4.9). …

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