Sign Up

Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.

Have an account? Sign In

Have an account? Sign In Now

Sign In

Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.

Sign Up Here

Forgot Password?

Don't have account, Sign Up Here

Forgot Password

Lost your password? Please enter your email address. You will receive a link and will create a new password via email.

Have an account? Sign In Now

You must login to ask a question.

Forgot Password?

Need An Account, Sign Up Here

Please briefly explain why you feel this question should be reported.

Please briefly explain why you feel this answer should be reported.

Please briefly explain why you feel this user should be reported.

Sign InSign Up

The Archive Base

The Archive Base Logo The Archive Base Logo

The Archive Base Navigation

  • Home
  • SEARCH
  • About Us
  • Blog
  • Contact Us
Search
Ask A Question

Mobile menu

Close
Ask a Question
  • Home
  • Add group
  • Groups page
  • Feed
  • User Profile
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Buy Points
  • Users
  • Help
  • Buy Theme
  • SEARCH
Home/ Questions/Q 772283
In Process

The Archive Base Latest Questions

Editorial Team
  • 0
Editorial Team
Asked: May 14, 20262026-05-14T18:47:00+00:00 2026-05-14T18:47:00+00:00

when I run this program while inputting a number greater than 46348, I get

  • 0

when I run this program while inputting a number greater than 46348, I get a segmentation fault. For any values below it, the program works perfectly. I am using CodeBlocks 8.02 on Ubuntu 10.04 64-bit.
The code is as follows:

int main()
{

    int number = 46348;
    vector<bool> sieve(number+1,false);
    vector<int> primes;
    sieve[0] = true;
    sieve[1] = true;

    for(int i = 2; i <= number; i++)
    {
        if(sieve[i]==false)
        {
            primes.push_back(i);
            int temp = i*i;
            while(temp <= number)
            {
                sieve[temp] = true;
                temp = temp + i;
            }
        }
    }

    for(int i = 0; i < primes.size(); i++)
        cout << primes[i] << " ";

    return 0;
}
  • 1 1 Answer
  • 0 Views
  • 0 Followers
  • 0
Share
  • Facebook
  • Report

Leave an answer
Cancel reply

You must login to add an answer.

Forgot Password?

Need An Account, Sign Up Here

1 Answer

  • Voted
  • Oldest
  • Recent
  • Random
  1. Editorial Team
    Editorial Team
    2026-05-14T18:47:01+00:00Added an answer on May 14, 2026 at 6:47 pm

    Assuming you are on a common architecture, the problem is that the i*i calculation overflows. The result can not be stored in a signed 32 bit integer. You can try adding cout << temp << endl; after this calculation. In the end it will print:

    2144523481
    2146190929
    2147117569
    -2146737495
    Segmentation fault
    

    For the future, you will want to run your code in a debugger. It lets you spot these things more easily. I suspect CodeBlocks offers a graphical debugger. (Otherwise, make sure to compile with -ggdb and run your program with gdb)


    Since you are on a 64 bit platform, you might want to use 64 bits unsigned integers to get a greater range. unsigned long long (C99, C++0x) is a good way to ask for “the biggest int you’ve got, that’s reasonably cheap”. (Even though one long long might span two registers, as is the case with a 64 bit datatype on IA32)


    Alternatively, you can add a check to automatically verify that number < sqrt(numeric_limits<int>::max()) before entering the loop.

    • 0
    • Reply
    • Share
      Share
      • Share on Facebook
      • Share on Twitter
      • Share on LinkedIn
      • Share on WhatsApp
      • Report

Sidebar

Related Questions

This is my problem. I have a program that has to run in a
When I run this code the selected item is not visible. I've already tried
when i run this code : CONADefinitions.CONAPI_FOLDER_INFO2 FolderInfo; int iResult = 0; IntPtr Buffer
Oracle is giving me an error (ORA-00907: missing right parenthesis) when I run this
With SQL Server 2005 using SSMS, when I run this: SELECT * FROM OPENROWSET('Microsoft.Jet.OLEDB.4.0','Excel
I'm working with a MySQL query that writes into an outfile. I run this
I run into this quite often where a new page is supposedly tested and
I receive this Run-Time Check Failure upon the return in the following code. I
Has anyone run into this error message before when using a timer on an
I've run into this issue quite a few times and never liked the solution

Explore

  • Home
  • Add group
  • Groups page
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Users
  • Help
  • SEARCH

Footer

© 2021 The Archive Base. All Rights Reserved
With Love by The Archive Base

Insert/edit link

Enter the destination URL

Or link to existing content

    No search term specified. Showing recent items. Search or use up and down arrow keys to select an item.