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Home/ Questions/Q 7597643
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Editorial Team
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Editorial Team
Asked: May 30, 20262026-05-30T22:12:24+00:00 2026-05-30T22:12:24+00:00

When I run this sample from the OptionParser documentation: require ‘optparse’ options = {}

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When I run this sample from the OptionParser documentation:

require 'optparse'
options = {}
OptionParser.new do |opts|
    opts.banner = "Usage: example.rb [options]"
    opts.on("-v", "--[no-]verbose", "Run verbosely") do |v|
        options[:verbose] = v
    end
end.parse!
p options
p ARGV

and type: ruby test.rb -v 100, it returns:

{:verbose=>true}
["100"]

Shouldn’t verbose be 100, not a boolean?

I have no idea about this, does anyone have any advice?

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  1. Editorial Team
    Editorial Team
    2026-05-30T22:12:25+00:00Added an answer on May 30, 2026 at 10:12 pm

    You’ve specified that the -v option does not have an argument:

    opts.on("-v", ...
    

    If you want it to take an argument then you have to say so:

    opts.on("-v n", "--verbose=n", ...
    #-----------^
    

    And if you want to force n to be an integer, then:

    opts.on('-v n', '--verbose=n', OptionParser::DecimalInteger, ...
    

    You want to start reading at the make_switch docs (such as it is) and then reverse engineer the examples.

    Don’t feel bad about being confused, the OptionParser documentation isn’t quite the best thing ever.

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