Question

When I tring to run this code any result not showing.Please help me

… some code is here…

$result = mysql_query("select  *  from dataform where  date between '" . $d1 . "' and '" . $d2 . "'");

if (!$result) {
    echo 'No result';
}
else{
    echo $d1;
    echo $d2;
    echo "<table class=\"hovertable\">";

    echo "
<tr onmouseover=\"this.style.backgroundColor='#ffff66';\" onmouseout=\"this.style.backgroundColor='#d4e3e5';\">";

    echo "<th>File No</th>";
    echo "<th>Manufactor</th>";
    echo "<th>Address</th>";
    echo "<th>Supplier</th>";
    echo "<th>Place Site</th>";
    echo "<th>Tender Ref</th>";
    echo "<th>Award No</th>";
    echo "</tr>";
    while ($row = mysql_fetch_array($result)) {
        echo "<tr onmouseover=\"this.style.backgroundColor='#ffff66';\" onmouseout=\"this.style.backgroundColor='#d4e3e5';\">";
        echo "<th>" . $row["fileno"] . "</th>";
        echo "<th>" . $row["manufacture"] . "</th>";
        echo "<th>" . $row["address"] . "</th>";
        echo "<th>" . $row["sup"] . "</th>";
        echo "<th>" . $row["placesite"] . "</th>";
        echo "<th>" . $row["tenderref"] . "</th>";
        echo "<th>" . $row["awardno"] . "</th>";
        echo "</tr>";
    }

Answer 1

Try escaping your column DATE with backtick ` because it is a MySQL Data type. Another Suggestion is avoidusing string concatenation of your query because it is prone to mysql injection. Use PHP PDO or MYSQLi.

Example of using PDO:

<?php
$stmt = $dbh->prepare("SELECT * FROM dataform WHERE  `date` BETWEEN ? AND ?");

$stmt->bindParam(1, $d1);
$stmt->bindParam(2, $d2);

$stmt->execute();

$result = $stmt->fetchAll(PDO::FETCH_ASSOC); //Fetch all results in form of associative array.

?>

Remember to always sanitize your inputs.

UPDATE 1

You are not checking for condition in your WHILE loop. The way you are doing now is you are assign a value which is wrong. Try using ==

instead of

while ($row = mysql_fetch_array($result))
{

}

change it to this

while ($row == mysql_fetch_array($result))
{

}