Question

When I Try to built Query from another Query in php code I Faced some problem
can you tell me why? 🙁

code :

$First="SELECT ro.RoomID,
               ro.RoomName,
               ro.RoomLogo,
               jr.RoomID,
               jr.MemberID,
               ro.RoomDescription 
          FROM joinroom jr,rooms ro 
         where (ro.RoomID = jr.RoomID)
           AND jr.MemberID = '1' ";

$sql1 = mysql_query($First);

$constract .= "ro.RoomName LIKE '%$search_each%'";
$constract="SELECT * FROM $sql1 WHERE $constract ";// This statment is Make error 

thanks ,Query it is Work now ! ..

But I Faced another problem ,When I Display the Result of this Query ..

code :

$run =mysql_query ($sql);

while($runrows=mysql_fetch_assoc($run))         
{
  $RoomName=$runrows["ro.RoomName"];
  $RoomDescription=$runrows["ro.RoomDescription"];

  echo "<center><b>$RoomName</b><br>$RoomDescription<br></center>";
}

Answer 1

Regarding the last part of the error, which you are facing, you need to remove the prefix “ro.” from the right hand parts of the assignment statements.

So your actual code should have been:-

$run = mysql_query ($sql);
while($runrows = mysql_fetch_assoc($run)) {
    $RoomName = $runrows["RoomName"];
    $RoomDescription = $runrows["RoomDescription"];

    echo "$RoomName $RoomDescription";
}

Try this one above, & you should be working fine; until & unless there is some error regarding your field’s existence in your database table or your database connection.