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Home/ Questions/Q 8967273
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Editorial Team
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Editorial Team
Asked: June 15, 20262026-06-15T17:12:21+00:00 2026-06-15T17:12:21+00:00

When i try to compile the following code, i get the error test.c: In

  • 0

When i try to compile the following code, i get the error

test.c: In function 'main':
test.c:16: error: incompatible types in assignment

and the code is..

#include <stdio.h>
#include <ctype.h>
#include <string.h>

typedef struct {
    char name[20];
    struct planet* next;
} planet;


int main(int argc, char *argv[])
{
    planet *p, *start, *first, *second, *third;

    strcpy(start->name, "Suthan");
    start->next = *first;

}
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-15T17:12:22+00:00Added an answer on June 15, 2026 at 5:12 pm

    1) Allocate some memory to your pointers.

    planet *start, *first; these are uninitialized pointers.
    
    start->next // that's dereferencing an uninitialized pointer.
    

    2) You’re setting start->next (a pointer to a planet) to a deferenced pointer first. That’s the root of your error.

    start->next = *first;  // should be  = first;
    

    3) Move the typedef name to get rid of the warning you were seeing.

    typedef struct planet{
       char name[20];
       struct planet* next;
    };
    
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