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Home/ Questions/Q 227111
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Editorial Team
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Editorial Team
Asked: May 11, 20262026-05-11T19:34:17+00:00 2026-05-11T19:34:17+00:00

When I try to put a zlibbed string in models.TextField >>> f = VCFile(head

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When I try to put a zlibbed string in models.TextField

>>> f = VCFile(head = 'blahblah'.encode('zlib'))
>>> f.save()

it fails:

    ...
raise DjangoUnicodeDecodeError(s, *e.args)
DjangoUnicodeDecodeError: 'utf8' codec can't decode byte 0x9c in position 1: unexpected code byte. You passed in 'x\x9cK\xcaI\xccH\x02b\x00\x0eP\x03/' (<type 'str'>)

Is there any way to fix this (apart from escaping the string – it has to be space-efficent)?

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  1. Editorial Team
    Editorial Team
    2026-05-11T19:34:17+00:00Added an answer on May 11, 2026 at 7:34 pm

    Like Marcus says, you’ll have to use BLOB if you want to keep it in binary format. If you’re OK with encoding it, you can use base64 encoding:

    from base64 import binascii
    
    f = VCFile(head = binascii.b2a_base64('blahblah'.encode('zlib')))
    

    In my very basic tests with 33k characters, the zlib string was 28% the size of the original string, the base64 encoded zlib string was 37% the size of the original string. Not quite as good on compression, but still a big improvement.

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