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Home/ Questions/Q 7614789
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Editorial Team
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Editorial Team
Asked: May 31, 20262026-05-31T02:29:33+00:00 2026-05-31T02:29:33+00:00

When I try to syncdb I get the error Menu is not a valid

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When I try to syncdb I get the error Menu is not a valid class Name.

How can I resolve that relationship case :

class MenuItem(model.Models)
    title = models.CharField(max_length=200)
    submenus = models.ManyToManyField(Menu, blank=True, null=True)

class Menu(Container):
    links = models.ManyToManyField(MenuItem)
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  1. Editorial Team
    Editorial Team
    2026-05-31T02:29:34+00:00Added an answer on May 31, 2026 at 2:29 am

    From the Django book:

    If you need to create a relationship on a model that has not yet been
    defined, you can use the name of the model, rather than the model
    object itself:

    E.g.:

    class MenuItem(model.Models)
        title = models.CharField(max_length=200)
        submenus = models.ManyToManyField('Menu', blank=True, null=True)
                                          ^    ^
    

    Edit:
    As Francis mentions (and as is written in the documentation):

    It doesn’t matter which model has the ManyToManyField, but you should only put it in one of the models — not both.

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