Home/ Questions/Q 8149313
In Process

The Archive Base Latest Questions

Editorial Team
  • 0
Asked: 2026-06-06T14:49:32+00:00

When i use following: var child:DisplayObjectContainer = dso.getChildAt( dso.numChildren -1 ) as DisplayObjectContainer; trace(child);

  • 0

When i use following:

var child:DisplayObjectContainer = dso.getChildAt( dso.numChildren -1 ) as DisplayObjectContainer;
trace(child); // [object MenuView]

My question now is if i want to use a if-case to see that it really is MenuView… something like:

if( child == 'MenuView'){...

I can not figure it out how to set such if case into work :S

Share

Leave an answer

You must login to add an answer.

Need An Account,

1 Answer

  1. Editorial Team

    You can use is operator:

    if( child is MenuView){

    Update: If importing MenuView class is impossible in your case, then you can try to use describeType global function:

    //if 'MenuView' class does not have 'namespace'
if( describeType(child).@name == "MenuView" ){ 

//if 'MenuView' class does have 'namespace'
if( describeType(child).@name.indexOf('MenuView') !== -1 ){
    • 0