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Home/ Questions/Q 8662909
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Editorial Team
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Editorial Team
Asked: June 12, 20262026-06-12T16:50:57+00:00 2026-06-12T16:50:57+00:00

When I use, for example, the command grep -c a output output2 | sed

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When I use, for example, the command

grep -c "a" output output2 | sed 's/[^0-9]//g'

the result is 0 for output and 20 for output2 because of its name. I want to ignore that 2 in output2‘s name. How can I do that, knowing that name can be different, for example output3?

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  1. Editorial Team
    Editorial Team
    2026-06-12T16:50:59+00:00Added an answer on June 12, 2026 at 4:50 pm

    Just cut everything but the number at the very end.

    grep -c "a" output output2 | sed 's/^.*:\([0-9]*\)/\1/'
    
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