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Home/ Questions/Q 6907339
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Editorial Team
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Editorial Team
Asked: May 27, 20262026-05-27T08:25:21+00:00 2026-05-27T08:25:21+00:00

when I use prolog’s built-in predicate subtract/3 : subtract(+Set, +Delete, -Result) in for example:

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when I use prolog’s built-in predicate “subtract/3” : subtract(+Set, +Delete, -Result) in for example:

subtract([a,b,c,d,c,c,d,e], [c,a], X).  
X = [b, d, d, e].  

but I want to subtract each item in +Delete from +Set ONCE. I mean, I want

subtract([a,b,c,d,c,c,d,e], [c,a], X). to give
X = [b, d, c, c, d, e].

How can I do this?

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  1. Editorial Team
    Editorial Team
    2026-05-27T08:25:21+00:00Added an answer on May 27, 2026 at 8:25 am

    You can build your own procedure that does that.
    For example:

    subtract_once(List, [], List).
    subtract_once(List, [Item|Delete], Result):-
      (select(Item, List, NList)->
        subtract_once(NList, Delete, Result);
        (List\=[],subtract_once(List, Delete, Result))).
    

    In every iteration you take one item from the list of items to remove, and extract one element from the input list, and then continue using the remainder of both lists.

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