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Editorial Team
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Asked: 2026-05-29T08:11:21+00:00

When I use responseText, I get all the data. From <HTML> to </HTML> .

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When I use responseText, I get all the data. From <HTML> to </HTML>. How to I extract specific parts of it? For example, I have this code:

<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
    <head>
        <meta http-equiv="Content-Type" content="text/html; charset=utf-8" />
        <title>Tester</title>
    </head>

    <body>

        <table>
            <tr>
                <td><a name="Name"></a>Name</td>
                <td>John</td>
            </tr>
            <tr>
                <td><a name="Email"></a>Email</td>
                <td>john@aol.com</td>
            </tr>
            <tr>
                <td><a name="Address"></a>Address</td>
                <td>123 Elm Street</td>
            </tr>
            <tr>
                <td><a name="City"></a>City</td>
                <td>Los Angeles</td>
            </tr>
            <tr>
                <td><a name="State"></a>State</td>
                <td>CA</td>
            </tr>
        </table>

    </body>
</html>

And Then I need to just extract like the city part Los Angeles. How would I go about doing this? I can’t do responseText.getElementByTagName, or anything like that.

Here’s the AJAX call:

var xmlhttp;
if (window.XMLHttpRequest)
  {// code for IE7+, Firefox, Chrome, Opera, Safari
  xmlhttp=new XMLHttpRequest();
  }
else
  {// code for IE6, IE5
  xmlhttp=new ActiveXObject("Microsoft.XMLHTTP");
  }
xmlhttp.onreadystatechange=function()
  {
  if (xmlhttp.readyState==4 && xmlhttp.status==200)
    {
    var pageContents = xmlhttp.responseText;
    document.getElementById("myDiv").innerText = pageContents;

    }
  }
xmlhttp.open("GET","content.html",false);
xmlhttp.send();
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1 Answer

  1. Editorial Team

    For a pure JavaScript solution, try (untested):

    var city = responseXML.getElementsByName('City').parentNode.nextElementSibling.childNodes[0].getAttribute('textContent');

    That said, a JavaScript library, like jQuery, to do the heavy lifting sure makes your code a lot easier to read (as well as cross-browser friendly).

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