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Home/ Questions/Q 8827959
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Editorial Team
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Editorial Team
Asked: June 14, 20262026-06-14T07:29:52+00:00 2026-06-14T07:29:52+00:00

When i use this script it ends up with the red one because that

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When i use this script it ends up with the red one because that is the last one in line.
So somehow I need to add z-index:+1 ?

jsfiddle.net/fourroses666/MCDw7

Anyone who can help me with this?

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  1. Editorial Team
    Editorial Team
    2026-06-14T07:29:53+00:00Added an answer on June 14, 2026 at 7:29 am

    This is not an answer to your question, but might be the solution you are seeking. So if you want continous fading of images. You should have two images, the background one having its opacity set to 1, the foreground one fading from 0 to 1. After it reached 1, you place the foreground image to the background, and add a new image into the foreground with opacity 0…

    Here is it on JSFiddle

    JS Code:

    function changeImg(){
        var img1 = document.getElementById("1");
        var img2 = document.getElementById("2");
        img1.src = img2.src;
        $("#2").css({ opacity: 0 });
        var randomNumber = Math.floor(Math.random()*(16*16*16 - 1));
        var randomStr = randomNumber.toString(16);
        img2.src = "http://dummyimage.com/50/" + randomStr + "/" + randomStr;
        $('#2').delay(200).animate({opacity:1},150, function(){
                changeImg();
        });
    
    }
    
    $(document).ready(function(){   
        changeImg();
    });​
    

    HTML Code:

    <div id="container">
        <img id="1" src="http://dummyimage.com/50/000/000" />
        <img id="2"/>    
    </div>​​​​​
    

    CSS Code:

    div img{
        position:absolute;
        width: 50px;
        opacity:1;
    }
    
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