Question

when i want to convert a date so that i can “feed” it to MySQL (mm/dd/yyyy -> yyyy-mm-dd) this preg_match works fine

$new_date = preg_replace("!([01][0-9])/([0-9]{2})/([0-9]{4})!", "$3-$1-$2", $data[$c]);

with dates like

04/02/2012, 12/31/2012

but it fails when i get input like

12/1/2011, 1/4/2011

how to fix it due to i’m total noob to regex… 🙁

Thanks a lot for your help.

Answer 1

Try:

!(\d{1,2})/(\d{1,2})/(\d{4})!

\d means a digit, and I think it’s handier than [0-9], and they are almost equivalent.