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Home/ Questions/Q 514319
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Editorial Team
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Editorial Team
Asked: May 13, 20262026-05-13T07:30:45+00:00 2026-05-13T07:30:45+00:00

when I want to execute some shell script in Unix (and let’s say that

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when I want to execute some shell script in Unix (and let’s say that I am in the directory where the script is), I just type:

./someShellScript.sh

and when I want to “source” it (e.g. run it in the current shell, NOT in a new shell), I just type the same command just with the “.” (or with the “source” command equivalent) before it:

. ./someShellScript.sh

And now the tricky part. When I want to execute “multiple” shell scripts (let’s say all the files with .sh suffix) in the current directory, I type:

find . -type f -name *.sh -exec {} \;

but “what command should I use to “SOURCE” multiple shell scripts in a directory”?
I tried this so far but it DIDN’T work:

find . -type f -name *.sh -exec . {} \;

and it only threw this error:

find: `.': Permission denied

Thanks.

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  1. Editorial Team
    Editorial Team
    2026-05-13T07:30:45+00:00Added an answer on May 13, 2026 at 7:30 am
    for file in *.sh
    do . $file
    done
    
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