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Home/ Questions/Q 7492331
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Editorial Team
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Editorial Team
Asked: May 29, 20262026-05-29T16:25:08+00:00 2026-05-29T16:25:08+00:00

When I want to instantiate a class in C++ I usually go this way

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When I want to instantiate a class in C++ I usually go this way

Book bk = new Book();

My professor recently did this

Book &bk = *new Book();

He only told me that he would use a reference to be able to use the dot (eg bk.getTitle();) operator instead of arrow (eg bk->getTitle();). I understand this part of the code but what happens when you use the * operator in combination with new?

Thanks in advance

the full example code can be found here it is the arraystack in the main function

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  1. Editorial Team
    Editorial Team
    2026-05-29T16:25:10+00:00Added an answer on May 29, 2026 at 4:25 pm

    This:

    Book &bk = *new Book();
    

    is pretty much equivalent to this:

    Book *p = new Book();  // Pointer to new book
    Book &bk = *p;  // Reference to that book
    

    But there’s one crucial difference; in the original code, you don’t have a pointer which you can use to delete the dynamically-allocated object when you’re done with it, so you’ve effectively created a memory leak.

    Of course, you could do this:

    delete &bk;
    

    but that’s extremely non-idiomatic C++, and very likely to cause problems later.

    In summary, there’s absolutely no good reason to write code like this, so don’t do it. Either of the following is fine:

    Book bk;
    Book bk = Book();
    
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