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Home/ Questions/Q 8474873
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Editorial Team
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Editorial Team
Asked: June 10, 20262026-06-10T17:44:31+00:00 2026-06-10T17:44:31+00:00

When I write the code below everything is reversed on output as expected. var

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When I write the code below everything is reversed on output as expected.

var sequence = "kick snare hat openHat";
var sequenceBackwards = sequence.split('').reverse().join('');
document.write(sequenceBackwards);

However when I have an Array, then convert it to a string then do the same proceedure it doesn’t work.

var sequence = ["kick","snare", "hat","openHat"];
sequence.toString();
var sequenceBackwards = sequence.split('').reverse().join('');
document.write(sequenceBackwards);

I would like to know exactly why this doesn’t work, and a working alternate example.

When I do a “typeof” for sequenceBackwards it doesn’t return string.It returns object which tells me it’s still an array after the supposed “conversion”. I’m a bit confused on this.

I am not doing this for a project I’m curious and have been picking at it for an hour.

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  1. Editorial Team
    Editorial Team
    2026-06-10T17:44:33+00:00Added an answer on June 10, 2026 at 5:44 pm

    This line does not change sequence variable, it just returns string:

    sequence.toString();

    ["kick", "snare", "hat", "openHat"].toString() provides "kick,snare,hat,openHat". So it is not what are you looking for.

    Use

    var sequence = ["kick", "snare", "hat", "openHat"];
    var sequenceBackwards = sequence.join(' ').split('').reverse().join('');
    document.write(sequenceBackwards);
    
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