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Home/ Questions/Q 995891
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Editorial Team
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Editorial Team
Asked: May 16, 20262026-05-16T06:47:33+00:00 2026-05-16T06:47:33+00:00

when I write this piece of String path=d:\\test.txt; boolean chk; File f=new File(path); try

  • 0

when I write this piece of

String path="d:\\test.txt";
    boolean chk;
    File f=new File(path);

    try
    {
        chk=f.createNewFile();
    }catch(IOException e)
    {
        chk=false;
        e.printStackTrace();
    }


    if(chk)
        System.out.println("file created.");
    else
        System.out.println("file not created");

file is created in d-drive

but when I use this

String path="d:\\test.txt";
    File f=new File(path);

    if(f.createNewFile())
        System.out.println("file created.");
    else
        System.out.println("file not created");

it throws exception.

Please enlighten me on this

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-16T06:47:34+00:00Added an answer on May 16, 2026 at 6:47 am

    Change second part of you code to following:

                        String path = "d:\\test.txt";
                        File f = new File(path);
    
                        try {
                            if (f.createNewFile())
                                System.out.println("file created.");
                            else
                                System.out.println("file not created");
                        } catch (IOException e1) {
                            e1.printStackTrace();
                        }
    

    You are required to do this because if you don’t surrond f.createNewFile() within try/catch block, your code won’t compile. As usage of f.createNewFile() throws IOException you need to either put it in try/catch block catching IOException or method using this part of code needs to declare throws IOException.

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