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Editorial Team
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Asked: 2026-06-06T05:05:28+00:00

When I’m calling RequestDispatcher, instead of processing request, JSP page itself is being rendered

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When I’m calling RequestDispatcher, instead of processing request, JSP page itself is being rendered as output…JSP content is present after “Account Created” line.

//Servlet block 

if(i==1){
            PrintWriter pw = response.getWriter();
            pw.println("Account Created!!");
            RequestDispatcher rd = request.getRequestDispatcher("Login.jsp");
            rd.include(request, response);
            System.out.println("Record Updated!!!");
        }

//Output rendered on browser:

Account Created!!

<!DOCTYPE html PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN"   "http://www.w3.org/TR/html4/loose.dtd">
<html>
<link rel="icon" type="image/ico" href="favicon.ico"></link> 
<link rel="shortcut icon" href="favicon.ico"></link>
<head>
<meta http-equiv="Content-Type" content="text/html; charset=ISO-8859-1">
<title>Login Page</title>
</head>
<body>
<form action="./Authentication" method="post">
    <p>Enter username<input type="text" name="Uname"></p>
    <p>Enter password<input type="password" name="Pword"></p>
    <input type="submit" value="Login"> 
</form>
</body>
</html>
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1 Answer

  1. Editorial Team

    You should not be getting the writer in the servlet and you should not be manually writing a string to it and you should be using RequestDispatcher#forward() instead of include(). You’re otherwise preventing JSP from setting the proper text/html content type and hence everything is interpreted as plain text by the webbrowser.

    Rewrite that servlet block as follows to let JSP do its job properly:

    if (i == 1) {
    request.getRequestDispatcher("Login.jsp").forward(request, response);
}

    See also:

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