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Home/ Questions/Q 9260685
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Editorial Team
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Editorial Team
Asked: June 18, 20262026-06-18T12:57:23+00:00 2026-06-18T12:57:23+00:00

When implementing Carmack’s Inverse Square Root algorithm I noticed that the results seem biased.

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When implementing “Carmack’s Inverse Square Root” algorithm I noticed that the results seem biased. The following code seems to give better results:

float InvSqrtF(float x)
{
    // Initial approximation by Greg Walsh.
    int i  = * ( int* ) &x;
    i  = 0x5f3759df - ( i >> 1 );
    float y  = * ( float * ) &i;
    // Two iterations of Newton-Raphson's method to refine the initial estimate.
    x *= 0.5f;
    float f = 1.5F;
    y  = y * ( f - ( x * y * y ) );
    y  = y * ( f - ( x * y * y ) );
    * ( int * )(&y) += 0x13; // More magic.
    return y;
}

The key difference is in the penultimate “more magic” line. Since the initial results were too low by a fairly constant factor, this adds 19 * 2^(exponent(y)-bias) to the result with just a single instruction. It seems to give me about 3 extra bits, but am I overlooking something?

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  1. Editorial Team
    Editorial Team
    2026-06-18T12:57:24+00:00Added an answer on June 18, 2026 at 12:57 pm

    Newton’s method produces a bias. The function whose zero is to be found,

    f(y) = x - 1/y²
    

    is concave, so – unless you start with an y ≥ √(3/x) – the Newton method only produces approximations ≤ 1/√x (and strictly smaller, unless you start with the exact result) with exact arithmetic.

    Floating point arithmetic occasionally produces too large approximations, but typically not in the first two iterations (since the initial guess usually isn’t close enough).

    So yes, there is a bias, and adding a small quantity generally improves the result. But not always. In the region around 1.25 or 0.85 for example, the results without the adjustment are better than with. In other regions, the adjustment yields one bit of additional precision, in yet others more.

    In any case, the magic constant to add should be adjusted to the region from which x is most often taken for the best results.

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