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Home/ Questions/Q 6245301
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Editorial Team
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Editorial Team
Asked: May 24, 20262026-05-24T12:28:50+00:00 2026-05-24T12:28:50+00:00

when playing with my project i need to debug it, and i like the

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when playing with my project i need to debug it, and i like the system of jsFiddle, so i’m developing on it directly

Problem is I have XML with Element named link which is completely different from HTML’s link

When I try to parse it via javascript, it tells me that link doesn’t have any childnodes because of HTML DTD used (no matter which i select)

I tried adding
<?xml version="1.0"?> <!DOCTYPE rootElement [ .. dtd declarations.. ]>
to top of code, but this won’t help

Is it possible to use jsFiddle with own DTD or not? if it is, how can i achieve this?

Thanks

code sample

<wrap>
    <link attribute=value>
        <child_node></child_node>
    </link>
</wrap>

when I use

var wrap = document.getElementsByTagName("wrap");
wrap = wrap[0];
var lnk = wrap.getElementsByTagName("link");
lnk = lnk[0];
document.write(lnk.getElementsByTagName("child_node"));

where wrap and link are objects of HTMLElement
it will show empty array
but those childs are accessible through childNodes property

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-24T12:28:50+00:00Added an answer on May 24, 2026 at 12:28 pm

    You would have to check if dtd accepts secondary declarations, in my opinion it would parse the page the way you put it, to show the exact results.

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