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Home/ Questions/Q 799315
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Editorial Team
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Editorial Team
Asked: May 14, 20262026-05-14T23:06:23+00:00 2026-05-14T23:06:23+00:00

When push_back method of vector is called the previous object in the vector is

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When push_back method of vector is called the previous object in the vector is getting destroyed what might be the reason for this.

template<typename type> void SomeList<type>::AddElement(type &inObject)
{
    pList.push_back(inObject);// pList is member of my class Vector SomeList 
}
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  1. Editorial Team
    Editorial Team
    2026-05-14T23:06:24+00:00Added an answer on May 14, 2026 at 11:06 pm

    The vector doesn’t destroy the object. It replaces it.

    For example:

    vector< A> myVector; // Do some initialization, etc.
    A myNewObject;
    myVector[0] = myNewObject; // Replace the object.
    

    That means the assignment operator (A& A::operator=( const A&)) will be called for myVector[0]. There is no destruction there.

    The destruction is done when the vector itself is destructed, or when the memory is reallocated (in this case, the copy constructor is also used, to copy the objects from the old location to the new location, before destroying the old ones).

    Later edit
    In push_back case, the destruction must be determined by a reallocation.

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