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Home/ Questions/Q 8658609
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Editorial Team
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Editorial Team
Asked: June 12, 20262026-06-12T15:48:37+00:00 2026-06-12T15:48:37+00:00

When running the following code the CPU load goes way up and it takes

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When running the following code the CPU load goes way up and it takes a long time on larger documents:

string pattern = @"\w+([-+.]\w+)*@\w+([-.]\w+)*\.\w+([-.]\w+)*";
Regex regex = new Regex(
      pattern,
      RegexOptions.None | RegexOptions.Multiline | RegexOptions.IgnoreCase);

MatchCollection matches = regex.Matches(input); // Here is where it takes time
MessageBox.Show(matches.Count.ToString());

foreach (Match match in matches)
{
    ...
}

Any idea how to speed it up?

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  1. Editorial Team
    Editorial Team
    2026-06-12T15:48:38+00:00Added an answer on June 12, 2026 at 3:48 pm

    Changing RegexOptions.None | RegexOptions.Multiline | RegexOptions.IgnoreCase to RegexOptions.Compiled yields the same results (since your pattern does not include any literal letters or ^/$).

    On my machine this reduces the time taken on the sample document you linked from 46 seconds to 21 seconds (which still seems slow to me, but might be good enough for you).

    EDIT: So I looked into this some more and have discovered the real issue.

    The problem is with the first half of your regex: \w+([-.]\w+)*\.\w+([-.]\w+)*@. This works fine when matching sections of the input that actually contain the @ symbol, but for sections that match just \w+([-.]\w+)*\.\w+([-.]\w+)* but are not followed by @, the regex engine wastes a lot of time backtracking and retrying from each position in the sequence (and failing again because there is still no @!)

    You can fix this by forcing the match to start at a word boundary using \b:

     string pattern = @"\b\w+([-+.]\w+)*@\w+([-.]\w+)*\.\w+([-.]\w+)*";
    

    On your sample document, this produces the same 10 results in under 1 second.

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