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Home/ Questions/Q 8645321
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Editorial Team
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Editorial Team
Asked: June 12, 20262026-06-12T12:31:18+00:00 2026-06-12T12:31:18+00:00

When subsetting arrays, R behaves differently depending on whether one of the dimensions is

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When subsetting arrays, R behaves differently depending on whether one of the dimensions is of length 1 or not. If a dimension has length 1, that dimension is lost during subsetting:

ax <- array(1:24, c(2,3,4))
ay <- array(1:12, c(1,3,4))
dim(ax)
#[1] 2 3 4
dim(ay)
#[1] 1 3 4
dim(ax[,1:2,])
#[1] 2 2 4
dim(ay[,1:2,])
#[1] 2 4

From my point of view, ax and ay are the same, and performing the same subset operation on them should return an array with the same dimensions. I can see that the way that R is handling the two cases might be useful, but it’s undesirable in the code that I’m writing. It means that when I pass a subsetted array to another function, the function will get an array that’s missing a dimension, if I happened to reduce a dimension to length 1 at an earlier stage. (So in this case R’s flexibility is making my code less flexible!)

How can I prevent R from losing a dimension of length 1 during subsetting? Is there another way of indexing? Some flag to set?

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  1. Editorial Team
    Editorial Team
    2026-06-12T12:31:19+00:00Added an answer on June 12, 2026 at 12:31 pm

    As you’ve found out by default R drops unnecessary dimensions. Adding drop=FALSE while indexing can prevent this:

    > dim(ay[,1:2,])
    [1] 2 4
    > dim(ax[,1:2,])
    [1] 2 2 4
    > dim(ay[,1:2,,drop = F])
    [1] 1 2 4
    
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