Sign Up

Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.

Have an account? Sign In

Have an account? Sign In Now

Sign In

Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.

Sign Up Here

Forgot Password?

Don't have account, Sign Up Here

Forgot Password

Lost your password? Please enter your email address. You will receive a link and will create a new password via email.

Have an account? Sign In Now

You must login to ask a question.

Forgot Password?

Need An Account, Sign Up Here

Please briefly explain why you feel this question should be reported.

Please briefly explain why you feel this answer should be reported.

Please briefly explain why you feel this user should be reported.

Sign InSign Up

The Archive Base

The Archive Base Logo The Archive Base Logo

The Archive Base Navigation

  • Home
  • SEARCH
  • About Us
  • Blog
  • Contact Us
Search
Ask A Question

Mobile menu

Close
Ask a Question
  • Home
  • Add group
  • Groups page
  • Feed
  • User Profile
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Buy Points
  • Users
  • Help
  • Buy Theme
  • SEARCH
Home/ Questions/Q 625701
In Process

The Archive Base Latest Questions

Editorial Team
  • 0
Editorial Team
Asked: May 13, 20262026-05-13T19:20:17+00:00 2026-05-13T19:20:17+00:00

When the run the following code, everything works fine until $i = 5. After

  • 0

When the run the following code, everything works fine until $i = 5. After that I get Uninitialized string offset notices, even though the arrays seem to be getting populated correctly. I get this notice when running locally but not when I check it on the remote server. Both are running v5.2.11. I assume the output is different from local to remote based on error reporting configs, but what is causing the notice?

Code:

$i = 0;
$row = 0;
$col = 0;
$quad = 0;
while(count($ripDigits) > 0)
{
    $ranNum = rand(0, count($ripDigits) - 1);
    $ripDigit_splice = array_splice($ripDigits, $ranNum, 1);
    $ranDigit = $ripDigit_splice[0];
    echo ("\$i = " . $i . " | count(\$ripDigits) = " . count($ripDigits) . "<br />\n");

    $thisRow = "row_" . $row;
    $$thisRow[$i] = $ranDigit;

    echo ("\t\t<td><b>" . $$thisRow[$i] . "</b></td>\n");

    $thisUsedColumn = "usedDigits_column_" . $i;
    $$thisUsedColumn[$col] = $$thisRow[$i];

    $thisUsedColumn = "usedDigits_quad_" . $i;
    $$thisUsedColumn[$quad] = $$thisRow[$i];

    $i++;
}

Output:

$i = 0 | count($ripDigits) = 8
$i = 1 | count($ripDigits) = 7
$i = 2 | count($ripDigits) = 6
$i = 3 | count($ripDigits) = 5
$i = 4 | count($ripDigits) = 4
$i = 5 | count($ripDigits) = 3

Notice: Uninitialized string offset: 5 in script.php on line 97

Notice: Uninitialized string offset: 5 in script.php on line 99

Notice: Uninitialized string offset: 5 in script.php on line 102

Notice: Uninitialized string offset: 5 in script.php on line 105
$i = 6 | count($ripDigits) = 2

Notice: Uninitialized string offset: 6 in script.php on line 97

Notice: Uninitialized string offset: 6 in script.php on line 99

Notice: Uninitialized string offset: 6 in script.php on line 102

Notice: Uninitialized string offset: 6 in script.php on line 105
$i = 7 | count($ripDigits) = 1

Notice: Uninitialized string offset: 7 in script.php on line 97

Notice: Uninitialized string offset: 7 in script.php on line 99

Notice: Uninitialized string offset: 7 in script.php on line 102

Notice: Uninitialized string offset: 7 in script.php on line 105
$i = 8 | count($ripDigits) = 0

Notice: Uninitialized string offset: 8 in script.php on line 97

Notice: Uninitialized string offset: 8 in script.php on line 99

Notice: Uninitialized string offset: 8 in script.php on line 102

Notice: Uninitialized string offset: 8 in script.php on line 105

1   8   4   2   7   5   9   3   6

Thanks in advance!

  • 1 1 Answer
  • 0 Views
  • 0 Followers
  • 0
Share
  • Facebook
  • Report

Leave an answer
Cancel reply

You must login to add an answer.

Forgot Password?

Need An Account, Sign Up Here

1 Answer

  • Voted
  • Oldest
  • Recent
  • Random
  1. Editorial Team
    Editorial Team
    2026-05-13T19:20:18+00:00Added an answer on May 13, 2026 at 7:20 pm

    Ok, I’m not really sure what the purpose of this is, so it’s hard to say… but I suspect this will be solved by using braces with your variable variables. It’s trying to use $thisRow[$i] as the variable name, but that doesn’t exist.

    $i = 0;
    $row = 0;
    $col = 0;
    $quad = 0;
    while(count($ripDigits) > 0) {
        $ranNum = rand(0, count($ripDigits) - 1);
        $ripDigit_splice = array_splice($ripDigits, $ranNum, 1);
        $ranDigit = $ripDigit_splice[0];
        echo ("\$i = " . $i . " | count(\$ripDigits) = " . count($ripDigits) . "<br />\n");
    
        $thisRow = "row_" . $row;
        ${$thisRow}[$i] = $ranDigit;
    
        echo ("\t\t<td><b>" . ${$thisRow}[$i] . "</b></td>\n");
    
        $thisUsedColumn = "usedDigits_column_" . $i;
        ${$thisUsedColumn}[$col] = ${$thisRow}[$i];
    
        $thisUsedColumn = "usedDigits_quad_" . $i;
        ${$thisUsedColumn}[$quad] = ${$thisRow}[$i];
    
        $i++;
    }
    

    This worked with ripDigits being initialized to an array of 6 numbers.

    Also, as to why it ‘works’ on the server – likely error reporting (E_NOTICE) is just turned off.

    • 0
    • Reply
    • Share
      Share
      • Share on Facebook
      • Share on Twitter
      • Share on LinkedIn
      • Share on WhatsApp
      • Report

Sidebar

Ask A Question

Stats

  • Questions 393k
  • Answers 393k
  • Best Answers 0
  • User 1
  • Popular
  • Answers
  • Editorial Team

    How to approach applying for a job at a company ...

    • 7 Answers
  • Editorial Team

    What is a programmer’s life like?

    • 5 Answers
  • Editorial Team

    How to handle personal stress caused by utterly incompetent and ...

    • 5 Answers
  • Editorial Team
    Editorial Team added an answer You have to write a mutation to evolve your database.… May 15, 2026 at 2:08 am
  • Editorial Team
    Editorial Team added an answer Well, PHP isn't really suited to the task. But then… May 15, 2026 at 2:08 am
  • Editorial Team
    Editorial Team added an answer You'll want to replace <!-- pagebreak --> with an actual… May 15, 2026 at 2:08 am

Trending Tags

analytics british company computer developers django employee employer english facebook french google interview javascript language life php programmer programs salary

Top Members

Explore

  • Home
  • Add group
  • Groups page
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Users
  • Help
  • SEARCH

Footer

© 2021 The Archive Base. All Rights Reserved
With Love by The Archive Base

Insert/edit link

Enter the destination URL

Or link to existing content

    No search term specified. Showing recent items. Search or use up and down arrow keys to select an item.